Oracle提供的序号函数
Oracle提供的序号函数:
以emp表为例:
1: rownum 最简单的序号 但是在order by之前就确定值.
select rownum,t.* from emp t order by ename
行数
ROWNUM
EMPNO
ENAME
JOB
MGR
HIREDATE
SAL
COMM
DEPTNO
1
11
7876
ADAMS
CLERK
7788
1987-5-23
1100
20
2
2
7499
ALLEN
SALESMAN
7698
1981-2-20
1600
300
30
3
6
7698
BLAKE
MANAGER
7839
1981-5-1
2850
30
4
7
7782
CLARK
MANAGER
7839
1981-6-9
2450
10
5
13
7902
FORD
ANALYST
7566
1981-12-3
3000
20
6
12
7900
JAMES
CLERK
7698
1981-12-3
950
30
7
4
7566
JONES
MANAGER
7839
1981-4-2
2975
20
8
9
7839
KING
PRESIDENT
1981-11-17
5000
10
9
5
7654
MARTIN
SALESMAN
7698
1981-9-28
1250
1400
30
10
14
7934
MILLER
CLERK
7782
1982-1-23
1300
10
11
8
7788
SCOTT
ANALYST
7566
1987-4-19
3000
20
12
1
7369
SMITH
CLERK
7902
1980-12-17
800
20
13
10
7844
TURNER
SALESMAN
7698
1981-9-8
1500
0
30
14
3
7521
WARD
SALESMAN
7698
1981-2-22
1250
500
30
2: row_number() over( order by 字段名1,字段名2,...字段名n ) 先排序再确定序号.
select row_number() over( order by ename ) as rm, t.* from emp t
行数
RM
EMPNO
ENAME
JOB
MGR
HIREDATE
SAL
COMM
DEPTNO
1
1
7876
ADAMS
CLERK
7788
1987-5-23
1100
20
2
2
7499
ALLEN
SALESMAN
7698
1981-2-20
1600
300
30
3
3
7698
BLAKE
MANAGER
7839
1981-5-1
2850
30
4
4
7782
CLARK
MANAGER
7839
1981-6-9
2450
10
5
5
7902
FORD
ANALYST
7566
1981-12-3
3000
20
6
6
7900
JAMES
CLERK
7698
1981-12-3
950
30
7
7
7566
JONES
MANAGER
7839
1981-4-2
2975
20
8
8
7839
KING
PRESIDENT
1981-11-17
5000
10
9
9
7654
MARTIN
SALESMAN
7698
1981-9-28
1250
1400
30
10
10
7934
MILLER
CLERK
7782
1982-1-23
1300
10
11
11
7788
SCOTT
ANALYST
7566
1987-4-19
3000
20
12
12
7369
SMITH
CLERK
7902
1980-12-17
800
20
13
13
7844
TURNER
SALES
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