Ò׽ؽØÍ¼Èí¼þ¡¢µ¥Îļþ¡¢Ãâ°²×°¡¢´¿ÂÌÉ«¡¢½ö160KB

pythonдµÄÖ¡·Ö¸îº¯Êý

ǰһÕóÔÚдһ¸ö×Ô¶¯²âÊÔ³ÌÐòʱÐèÒª°´ÕÕÌØ¶¨×Ö·û¶ÔÊÕµ½µÄÊý¾Ý½øÐÐÖ¡µÄ·Ö¸î£¬Ô­ÓÐÒªÇóÊÇÓÐÿ֡ǰºó¸÷ÓÐÒ»¸öͬÑùµÄÌØÊâ×Ö·û,µ±Ê±¹À¼ÆÏÂʱ¼ä»¹¹»£¬Ï뽫ÆäÀ©Õ¹ÎªÒ»¸ö½ÏΪͨÓù¦ÄÜ£¬¼´Ã¿Ö¡Êý¾ÝǰÓи÷ÓÐÒ»¸öÌØÊâ×Ö·û±íʾ¿ªÊ¼ºÍ½áÊø£¬µ«Ç°ºóÕâÁ½×Ö·û¿ÉÒÔ²»Í¬£¬Ò²¿ÉÒÔÖ»ÓÐÒ»¸ö£¨ÔÚÍ·ÔÚβ·Ö¸îЧ¹û²»Í¬£©£¬Í¬Ê±Ñ§Ï°ÁËÒ»Õópython£¬¸Ð¾õÆä´¦ÀíÕâÀàÎÊÌ⻹±È½ÏºÏÊÊ£¬Íê³ÉÁËÒÔϳõ²½µÄ´úÂ룬´Ë¶Î´úÂëÐÔÄÜÉÏ»¹ÐèÓÅ»¯£º
def frame_read(fd,head,tail,timeout):
    'return -- donot recv data return None,recv data but wrong format return [],else return data in tupe format, \
            frame_len -- each frame cmd len,'
    if fd is None or len <= 0:
        print 'fd is None or len <= 0,'
        return None
    fd_type = check_obj_type(fd)
#    print 'connect obj type is %s' % fd_type
    if fd_type == 'invalid_type':
        return None
    cur_time = time.time()
    data = ''
    lines = []
    received = False
    head_found = False
    head_len = len(head)
    tail_len = len(tail)
    temp = None
    frame_len = 512
    hex_str = ''
    while 1:
        if is_timeout(cur_time,timeout):
            print 'wait data timeout.'
            if not received:
                return None
            else:               
      


Ïà¹ØÎĵµ£º

һƪ²»´íµÄPythonÈëÃŽ̳Ì

Ô­ÎÄ
 http://www.hetland.org/python/instant-hacking.php
Instant Hacking[Òë
ÎÄ]
ÒëÕߣº ¿Ï¶¨À´¹ý                                ......

pythonµÄ±Õ°ü(3.0֮ǰ¼°Ö®ºó)

Ê×ÏÈ, ˵˵pythonÀïÃæµÄ±Õ°ü°É:
1. ÐèÒªº¯ÊýǶÌ×, ¾ÍÊÇÒ»¸öº¯ÊýÀïÃæÔÙдһ¸öº¯Êý.
2. Íⲿº¯ÊýÐèÒª·µ»ØÒ»¸öÄÚ²¿º¯ÊýµÄÒýÓÃ
3. Íⲿº¯ÊýÖÐÓÐһЩ¾Ö²¿±äÁ¿, ²¢ÇÒ, ÕâЩ¾Ö²¿±äÁ¿ÔÚÄÚ²¿º¯ÊýÖÐÓÐʹÓÃ
¸ÅÄî:
1. ×ÔÓɱäÁ¿: Íⲿº¯ÊýÖж¨ÒåµÄ¾Ö²¿±äÁ¿, ²¢ÇÒÔÚÄÚ²¿º¯ÊýÖб»Ê¹ÓÃ.
2. ±Õ°ü: ÄǸöʹÓÃÁË×ÔÓɱäÁ¿²¢±»·µ»ØµÄÄÚ²¿º¯Ê ......

Ò»¸ö¼õÉÙ¶à½ø³ÌÏÂpythonÄÚ´æÕ¼ÓõÄС¼¼ÇÉ

¡¡¡¡ÔÚpythonÖÐÈç¹ûҪʹÓÃfork»òÕßmultiprocessÀ´×ö¶à½ø³Ì£¬¼ÙÈçimportµÄ¿âºÜ¶à»òÕߺܴó£¬ÀýÈçwxpython£¬²é¿´¸÷½ø³ÌµÄÄÚ´æÕ¼ÓÃÄã»á·¢ÏÖÁ½¸ö½ø³ÌµÄÄÚ´æÕ¼Óûù±¾ÉÏÏàͬ£¬»»¾ä»°Ëµ£¬Èç¹ûµÚ¶þ¸ö½ø³Ì¸ù±¾²»ÐèÒªÓõ½wxµÄÄÚÈÝ£¬ËüÒ²»á±»¼ÓÔØµ½ÄÚ´æµ±ÖÐÈ¥¡£¾ÍÄÃwxÀ´×öÀý×Ó£¬Ã»ÓÐimport t wxÕ¼Óôó¸Å8M+Äڴ棬һµ©import wx£¬ÄÚ´æÂíÉ ......

ÉæË®The Python Challenge

ÔÚStack Overflow ÉÏ¿´µ½Ñ§Ï°Python µÄÒ»¸ö·½·¨ÊÇÓÃPython ÆÆ½âThe Python Challenge¡£µ«ÎÒϲ»¶ÓÃRuby£¬Ë­¹ÜµÃ×ÅÄØ^_^
0. ÈëÃŹغܼòµ¥¡£
p 2**38 
1. ÆÆ½âÒ»¶Î»°£¬¹Û²ìͼƬºÜÈÝÒ×·¢ÏÖ½âÂë±í°Ñ×Öĸ±íÑ­»·ÓÒÒÆÁ½Î»¡£
riddle = "g fmnc wms bgblr rpylqjyrc gr zw fylb. rfyrq ufyr amknsrcpq ypc dmp. bmgle gr gl ......
© 2009 ej38.com All Rights Reserved. ¹ØÓÚE½¡ÍøÁªÏµÎÒÃÇ | Õ¾µãµØÍ¼ | ¸ÓICP±¸09004571ºÅ