C# Access Update 注意事项
private const string ACCESS_UPDATE_ADMIN_PASSWORD = "UPDATE [Admins] SET admin_pass=@adminPass WHERE admin_name=@adminName";
dbInstance.SetParameters("@adminPass", _adminDObj.Admin_Password);
dbInstance.SetParameters("@adminName", _adminDObj.Admin_Name);
参数的顺序必须和SQL的顺序一直,否则无法更新。如上面这2行颠倒了,则会无法更新
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首先我很遗憾的告诉大家,因为微软的偷懒,目前UpdatePanel还不支持文件上传。变相的解决办法就是UpdatePanel中设置PostBackTrigger:
<asp:UpdatePanel ID="UpdatePanel1" runat="server">
<ContentTemplate>
<asp:FileUpload ID="FileUpload1" runat="serv ......
注意:
在使用FindControl时,一定要在最贴近查找对象的外边加上个容器,如果你直接用this.FindControl,或Page.FindControl那么就会经常出现未将对象设置到实例
的错误,所以最好加一个容器,那么这里加的DIV就是一个容器,为了让FindControl在ID为"TextBoxs"的DIV内去找名为com1,com2,com3的TextBOx;
<div ......
//读取标准列表
private void setModelList()
{
OleDbConnection Connection = null;
&n ......
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[C#]
public void RunSqlTransaction(string myConnString)
{
SqlConnection myConnection = new SqlConnection(myConnString);
myConnection.Open();
SqlCommand myCommand = myConnection.CreateCommand();
SqlTransaction m ......