C#序列化xml
关键步骤：
XmlSerializer xSerializer = new XmlSerializer(typeof(MyObj));
StringWriter sWriter = new StringWriter(CultureInfo.InvariantCulture);
XmlTextWriter xTextWriter = new XmlTextWriter(sWriter);
XmlDocument xmlDoc = new XmlDocument();
xSerializer.Serialize(xTextWriter, myObj);
xmlDoc.LoadXml(sWriter.ToString());
需要说明的是，如果要序列化的object所在的类里有带参数的构造函数，还必须添加一个无参数的构造函数，否则，会报object cannot be serialized because it does not have a parameterless constructor的错误。下面是一个完整的实例，仅供参考。
using System;
using System.Xml;
using System.Xml.Serialization;
using System.IO;
/* The XmlRootAttribute allows you to set an alternate name
(PurchaseOrder) of the XML element, the element namespace; by
default, the XmlSerializer uses the class name. The attribute
also allows you to set the XML namespace for the element. Lastly,
the attribute sets the IsNullable property, which specifies whether
the xsi:null attribute appears if the class instance is set to
a null reference. */
[XmlRootAttribute("PurchaseOrder", Namespace="http://www.cpandl.com",
IsNullable = false)]
public class PurchaseOrder
{
public Address ShipTo;
public string OrderDate;
/* The XmlArrayAttribute changes the XML element name
from the default of "OrderedItems" to "Items". */
[XmlArrayAttribute("Items")]
public OrderedItem[] OrderedItems;
public decimal SubTotal;
public decimal ShipCost;
public decimal TotalCost;
}
public class Address
{
/* The XmlAttribute instructs the XmlSerializer to serialize the Name
field as an XML attribute instead of an XML element (the default
behavior). */
[XmlAttribute]
public string Name;
public string Line1;
/* Setting the IsNull
XML Schema主要用来设计XML文档的结构，注意不是格式。有人问怎么不是格式？格式跟结构什么区别？我想搞开发的人都对代码进行格式化过，也就是缩进、字体等等；而我们写的程序实际上也是定义一种结构，它不会因为你是否缩进、采用不同的字体就有所改变吧？很多人哪了不分行的xml文档说用VS的工具� ......
/// <summary>
/// 方法一:通过使用 new 运算符创建对象
/// </summary>
/// <param name="strSource">需要加密的明文</param>
/// <returns>返回16位加密结果，该结果取32位加密结果的第9位到25位</returns>
public string Get_MD5_Method1(strin ......
--XQuery 基于现有的 XPath 查询语言，并支持更好的迭代、更好的排序结果以及构造必需的 XML 的功能。
--1.声明一个 xml 类型的变量，然后使用 xml 数据类型的 query() 方法来查询此变量
DECLARE @x xml
SET @x = '<ROOT><a>111</a></ROOT>'
SELECT @x.query('/ROOT/a')
--查找属性aid=20的a� ......
