MSSQL中计算两个日期之间相隔 xx天xx小时xx分xx秒
DECLARE @dt1 AS datetime, @dt2 AS datetime;
SELECT @dt1 = '2008-8-4 9:36:41', @dt2 = '2008-8-2 9:33:39';
DECLARE @Days AS int, @Hours AS int, @Minutes AS int, @Seconds AS int;
SET @Seconds = DATEDIFF( second, @dt2, @dt1);
SET @Days = @Seconds / (24 * 60 * 60)
SET @Seconds = @Seconds - @Days * 24 * 60 * 60
SET @Hours = @Seconds / (60 * 60);
SET @Seconds = @Seconds - @Hours * 60 * 60
SET @Minutes = @Seconds / 60;
SET @Seconds = @Seconds - @Minutes * 60;
SELECT CONVERT(varchar(10), @Days ) + '天'
+ CONVERT(varchar(10), @Hours ) + '小时'
+ CONVERT(varchar(10), @Minutes ) + '分'
+ CONVERT(varchar(10), @Seconds ) + '秒';
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select语句前加：
declare @d datetime
set @d=getdate()
并在select语句后加：
select [语句执行花费时间(毫秒)]=datediff(ms,@d,getdate())
转自：动态网制作指南 www.knowsky.com
这是简易的查看执行时间的方法。
===========================================（一下内容转自：ＣＳＤＮ）
MSSQL Server中通过查 ......
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D99_tmp（subdirectory,depth,file三个字段，里面的数据都是网站文件和目录）
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http://www.sqlhacks.com/Administration/Memory-Usage
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As an administrator, you should be monitoring the memory
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查询语句只要这样写,就可以随机取出记录了
SQL="Select top 6 * from Dv_bbs1 where isbest = 1 and layer = 1 order by newID() desc"
在ACCESS里
SELECT top 15 id from tablename order by rnd(id)
SQL Server：
Select TOP N * from TABLE Order By NewID()
Access：
Select TOP N * from TABLE Order By Rnd(ID ......
