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CREATE TABLE [StuInfo] (
[recno] [int] IDENTITY (1, 1) NOT NULL ,
[stuid] [varchar] (10) COLLATE Chinese_PRC_CI_AS NOT NULL ,
[stuname] [varchar] (10) COLLATE Chinese_PRC_CI_AS NOT NULL
) ON [PRIMARY]
GO
1.--²éijһÁÐ(»ò¶àÁÐ)µÄÖØ¸´Öµ(Ö»Äܲé³öÖØ¸´¼Ç¼µÄÖµ£¬²»ÄÜÕû¸ö¼Ç¼µÄÐÅÏ¢)
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select stuid,stuname from stuinfo
group by stuid,stuname
having(count(*))>1
2.--²éijһÁÐÓÐÖØ¸´ÖµµÄ¼Ç¼(ÕâÖÖ·½·¨²é³öµÄÊÇËùÓÐÖØ¸´µÄ¼Ç¼,Ò²¾ÍÊÇ˵Èç¹ûÓÐÁ½Ìõ¼ÇÂ¼ÖØ¸´µÄ£¬¾Í²é³öÁ½Ìõ)
--Èç:²éÕÒstuidÖØ¸´µÄ¼Ç¼
select * from stuinfo
where stuid in (
select stuid from stuinfo
group by stuid
having(count(*))>1
)
3.--²éijһÁÐÓÐÖØ¸´ÖµµÄ¼Ç¼(Ö»ÏÔʾ¶àÓàµÄ¼Ç¼,Ò²¾ÍÊÇ˵Èç¹ûÓÐÈýÌõ¼ÇÂ¼ÖØ¸´µÄ£¬¾ÍÏÔʾÁ½Ìõ)
--ÕâÖÖ·½³É¼¨µÄǰÌáÊÇ£ºÐèÓÐÒ»¸ö²»Öظ´µÄÁÐ,±¾ÀýÖеÄÊÇrecno
--Èç:²éÕÒstuidÖØ¸´µÄ¼Ç¼
select * from stuinfo s1
where recno not in (
select max(recno) from stuinfo s2
where s1.stuid=s2.stuid
)
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