create function fun_getPY(@str nvarchar(4000))
returns nvarchar(4000)
as
begin
declare @word nchar(1),@PY nvarchar(4000)
set @PY=''
while len(@str)>0
begin
set @word=left(@str,1)
--如果非汉字字符，返回原字符
set @PY=@PY+(case when unicode(@word) between 19968 and 19968+20901
then (select top 1 PY from (
select 'A' as PY,N'驁' as word
union all select 'B',N'簿'
union all select 'C',N'錯'
union all select 'D',N'鵽'
union all select 'E',N'樲'
union all select 'F',N'鰒'
union all select 'G',N'腂'
union all select 'H',N'夻'
union all select 'J',N'攈'
union all select 'K',N'穒'
union all select 'L',N'鱳'
union all select 'M',N'旀'
union all select 'N',N'桛'
union all select 'O',N'漚'
union all select 'P',N'曝'
union all select 'Q',N'囕'
union all select 'R',N'鶸'
union all select 'S',N'蜶'
union all select 'T',N'籜'
union all select 'W',N'鶩'
union all select 'X',N'鑂'
union all select 'Y',N'韻'
union all select 'Z',N'咗'
) T
where word>=@word collate Chinese_PRC_CS_AS_KS_WS
order by PY ASC) else @word end)
set @str=right(@str,len(@str)-1)
end
return @PY
end
--函数调用实例：
--select dbo.fun_getPY('中华人民共和国')
-----------------------------------------------------------------
--可支持大字符集20000个汉字!
create function f_ch2py(@chn nchar(1))
returns char(1)
as
begin
declare @n int
declare @c char(1)
set @n = 63
select @n = @n +1,
@c = case chn when @chn then char(@n) else @c end
from(
select top 27 * from (
select chn =
'吖' union all select
'八' union all select
'嚓' union all select
'咑' union all select
'妸' unio
--------------------------------查询系统库中是否有库（有库就删除此库）----------------------------------------------------
use master
if exists(select * from databases where name='库名')
drop database 库名
__________________________ 建数据库建表的基本格式 __________________ ......
